Answer
a). SI units of $IAB=(A)(m^{2})((T)=\frac{C}{s}\times m^{2}\times \frac{N}{C.(m/s)}=N.m$ which is the SI unit for torque.
b). If we are looking down onto an area of current-carrying loop and the current is counterclockwise, by right hand rule, the magnetic moment is out of the page towards us.
Work Step by Step
a). SI units of $IAB=(A)(m^{2})((T)=\frac{C}{s}\times m^{2}\times \frac{N}{C.(m/s)}=N.m$ which is the SI unit for torque.
b). If we are looking down onto an area of current-carrying loop and the current is counterclockwise, by right hand rule, the magnetic moment is out of the page towards us.
