College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 18 - Basic Electric Circuits - Learning Path Questions and Exercises - Exercises - Page 653: 12


$i=0.25A$ $V=2.5V$

Work Step by Step

$R_{1}$ and $R_{2}$ are parallel to each other, the equivalent of which are in series with $R_{3}$. Hence, equivalent Resistance = $\frac{10\times2}{12}+5=6.7Ohm$ $I=V/R=10/6.7=1.5A$ is the current in the circuit. So, current through the 10-Ohm = $\frac{2}{12}\times1.5=0.25A$ And voltage across 10-Ohm = $V=IR=0.25\times10=2.5V$
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