#### Answer

$i=0.25A$
$V=2.5V$

#### Work Step by Step

$R_{1}$ and $R_{2}$ are parallel to each other, the equivalent of which are in series with $R_{3}$.
Hence, equivalent Resistance = $\frac{10\times2}{12}+5=6.7Ohm$
$I=V/R=10/6.7=1.5A$ is the current in the circuit.
So, current through the 10-Ohm = $\frac{2}{12}\times1.5=0.25A$
And voltage across 10-Ohm = $V=IR=0.25\times10=2.5V$