## College Physics (7th Edition)

Published by Pearson

# Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Conceptual Questions - Page 618: 13

#### Answer

Diameter must be equal to $\frac{1}{\sqrt 2}$ times the original value.

#### Work Step by Step

$R=\frac{\rho l}{A}$ Length is halved, i.e., $l'=\frac{l}{2}$. If the new area $A'=\frac{A}{2}$, then $\frac{1}{2}$ in the numerator and $\frac{1}{2}$ in the denominator will get canceled and the resistance will be constant. $A'=\frac{A}{2} \implies \pi r_{2}^{2}=\frac{1}{2}\pi r_{1}^{2}$ $\implies r_{2}=\frac{r_{1}}{\sqrt 2}$ or $d_{2}=\frac{d_{1}}{\sqrt 2}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.