Answer
(a) $4.54\times10^{-9}\,C$
(b) $2.72\times10^{-8}\,J$
(c) $2.29\times10^{3}\,V/m$
Work Step by Step
(a) $q=CV=(\frac{\varepsilon_{0}A}{d})V$
$=(\frac{8.85\times10^{-12}\,F/m\times0.224\,m^{2}}{5.24\times10^{-3}\,m})12.0\,V=4.54\times10^{-9}\,C$
(b) $Energy=\frac{1}{2}CV^{2}=\frac{1}{2}(\frac{\varepsilon_{0}A}{d})\times V^{2}$
$=\frac{1}{2}\times(\frac{8.85\times10^{-12}\,F/m\times0.224\,m^{2}}{5.24\times10^{-3}\,m})\times(12.0\,V)^{2}$
$=2.72\times10^{-8}\,J$
(c) $E=\frac{V}{d}=\frac{12.0\,V}{5.24\times10^{-3}\,m}=2.29\times10^{3}\,V/m$
