## College Physics (7th Edition)

$+5.15\times10^{-11}C$
The charge on 1 electron =$-1.6\times10^{-19}C$ The electroscope will acquire the opposite of the charge lost due to electrons. The charge on electroscope = $+1.6\times10^{-19}\times3.22\times10^{8}C$=$+5.15\times10^{-11}C$