College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 15 - Electric Charge, Forces, and Fields - Learning Path Questions and Exercises - Exercises - Page 556: 7



Work Step by Step

The charge on 1 electron =$-1.6\times10^{-19}C$ The electroscope will acquire the opposite of the charge lost due to electrons. The charge on electroscope = $+1.6\times10^{-19}\times3.22\times10^{8}C$=$+5.15\times10^{-11}C$
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