College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 13 - Vibrations and Waves - Learning Path Questions and Exercises - Exercises - Page 484: 9

Answer

$0.5m/s$

Work Step by Step

$F=ma=0.1\times5=0.5N$ $F=kx$, Thus $0.5=10\times x$, $x=0.05m$ $E=0.5kx^{2}=0.5\times 10 \times 0.05^{2}=0.0125J $ Now, KE=$0.5mv^{2}$ $0.0125=0.5\times 0.1\times v^{2}$ So, $v=0.5m/s$
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