Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 384: 41

$\Delta T=9.52C^{\circ}$

We know that $\frac{\Delta V}{V}=b\Delta T $ We plug in the known values to obtain: $0.002=(2.1\times 10^{-4})\Delta T$ This can be rearranged as: $\Delta T=\frac{0.002}{2.1\times 10^{-4}}$ This simplifies to: $\Delta T=9.52C^{\circ}$