College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 384: 41


$\Delta T=9.52C^{\circ}$

Work Step by Step

We know that $\frac{\Delta V}{V}=b\Delta T $ We plug in the known values to obtain: $0.002=(2.1\times 10^{-4})\Delta T$ This can be rearranged as: $\Delta T=\frac{0.002}{2.1\times 10^{-4}}$ This simplifies to: $\Delta T=9.52C^{\circ}$
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