College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 382: 8


Her final temperature is $28.28^{\circ}C$ or $82.904^{\circ}F$

Work Step by Step

$C=\frac{F-32}{1.8}$ so, when F=98.2, $C=\frac{98.2-32}{1.8}=36.78$ her final temperature = $36.78-8.5=28.28^{\circ}C$ $F=1.8C+32=1.8\times 28.28+32=82.904^{\circ}F$
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