College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 9-12 - Review Exercises - Page 469: 14

Answer

The new fundamental frequency is $1467~Hz$

Work Step by Step

We can find an expression for the original fundamental frequency: $v = \sqrt{\frac{F}{\mu}}$ $\lambda~f = \sqrt{\frac{F}{\mu}}$ $f = \frac{1}{\lambda}~\sqrt{\frac{F}{\mu}}$ We can find the new fundamental frequency: $v' = \sqrt{\frac{F'}{\mu}}$ $\lambda~f' = \sqrt{\frac{F'}{\mu}}$ $f' = \frac{1}{\lambda}~\sqrt{\frac{F'}{\mu}}$ $f' = \frac{1}{\lambda}~\sqrt{\frac{3.0~F}{\mu}}$ $f' = \sqrt{3.0}\times \frac{1}{\lambda}~\sqrt{\frac{F}{\mu}}$ $f' = \sqrt{3.0}\times f$ $f' = \sqrt{3.0}\times (847~Hz)$ $f' = 1467~Hz$ The new fundamental frequency is $1467~Hz$
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