College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 6-8 - MCAT Review - Page 327: 14

Answer

The correct answer is: C. Equal

Work Step by Step

Let the magnitude of the work done initially by the pads be $F~d$. We can find the magnitude of the work done by the pads in the second workout: $Work = (\frac{F}{2})~(2d) = F~d$ Since the magnitude of the work done by the pads is equal to the energy dissipated, the two values are equal. The correct answer is: C. Equal
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