## College Physics (4th Edition)

Published by McGraw-Hill Education

# Review & Synthesis: Chapters 6-8 - MCAT Review - Page 327: 14

#### Answer

The correct answer is: C. Equal

#### Work Step by Step

Let the magnitude of the work done initially by the pads be $F~d$. We can find the magnitude of the work done by the pads in the second workout: $Work = (\frac{F}{2})~(2d) = F~d$ Since the magnitude of the work done by the pads is equal to the energy dissipated, the two values are equal. The correct answer is: C. Equal

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