## College Physics (4th Edition)

Let the magnitude of the work done initially by the pads be $F~d$. We can find the magnitude of the work done by the pads in the second workout: $Work = (\frac{F}{2})~(2d) = F~d$ Since the magnitude of the work done by the pads is equal to the energy dissipated, the two values are equal. The correct answer is: C. Equal