College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 16-18 - MCAT Review - Page 713: 10


The correct answer is: (C) $~100~A$

Work Step by Step

We can find the required current: $P = I~V$ $I = \frac{P}{V}$ $I = \frac{1.2\times 10^4~W}{120~V}$ $I = 100~A$ The correct answer is: (C) $~100~A$
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