Answer
The correct answer is: (C) $~100~A$
Work Step by Step
We can find the required current:
$P = I~V$
$I = \frac{P}{V}$
$I = \frac{1.2\times 10^4~W}{120~V}$
$I = 100~A$
The correct answer is: (C) $~100~A$
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