College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 9 - Problems - Page 368: 109


The density of the liquid is $0.83~g/cm^3$

Work Step by Step

We can see that the points $0.20~m$ above the bottom on both sides of the tube have the same pressure. Then the gauge pressure due to the fluid above this point must be equal on both sides of the tube. We can find the density $\rho_l$ of the liquid: $\rho_l~g~h_l = \rho_w~g~h_w$ $\rho_l = \frac{\rho_w~h_w}{h_l}$ $\rho_l = \frac{(1.0~g/cm^3)(0.25~m)}{0.30~m}$ $\rho_l = 0.83~g/cm^3$ The density of the liquid is $0.83~g/cm^3$.
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