## College Physics (4th Edition)

The average pressure on the soles of the feet is $22,050~N/m^2$
We can find the average pressure on the soles of the feet: $P = \frac{F}{A}$ $P = \frac{mg}{A}$ $P = \frac{(90.0~kg)(9.80~m/s^2)}{(2)(0.020~m^2)}$ $P = 22,050~N/m^2$ The average pressure on the soles of the feet is $22,050~N/m^2$