Answer
The average pressure on the soles of the feet is $22,050~N/m^2$
Work Step by Step
We can find the average pressure on the soles of the feet:
$P = \frac{F}{A}$
$P = \frac{mg}{A}$
$P = \frac{(90.0~kg)(9.80~m/s^2)}{(2)(0.020~m^2)}$
$P = 22,050~N/m^2$
The average pressure on the soles of the feet is $22,050~N/m^2$
