## College Physics (4th Edition)

The ratio of the moon's orbital speed at perigee to that at apogee is $1.14$
We can use conservation of angular momentum to find the ratio of the orbital speeds: $L_p = L_a$ $m~v_p~r_p = m~v_a~r_a$ $\frac{v_p}{v_a} = \frac{r_a}{r_p}$ $\frac{v_p}{v_a} = \frac{4.07\times 10^5~km}{3.56\times 10^5~km}$ $\frac{v_p}{v_a} = 1.14$ The ratio of the moon's orbital speed at perigee to that at apogee is $1.14$.