## College Physics (4th Edition)

$F = 200~N$
If the system is in equilibrium, the torque exerted by the applied force $F$ about the support must be equal in magnitude to the torque exerted by the weight about the support. We can find the applied force $F$: $r~F = r_w~mg$ $F = \frac{r_w~mg}{r}$ $F = \frac{(0.50~m)(1200~N)}{3.0~m}$ $F = 200~N$