## College Physics (4th Edition)

The magnitude of the torque that the cord applies to the drum is $~4.5~N\cdot m$
The torque is $\tau = r\times F$, where $r$ is the smallest distance between the force vector and the rotation axis, and $F$ is the perpendicular component of the force vector. We can find the magnitude of the torque: $\tau = r\times F$ $\tau = (0.060~m)(75~N)$ $\tau = 4.5~N\cdot m$ The magnitude of the torque that the cord applies to the drum is $~4.5~N\cdot m$