## College Physics (4th Edition)

The rotational inertia of the disk is $0.98~kg~m^2$
We can find the rotational inertia of the disk: $I = \frac{1}{2}MR^2 = \frac{1}{2}(49~kg)(0.20~m)^2 = 0.98~kg~m^2$ The rotational inertia of the disk is $0.98~kg~m^2$.