Answer
A kinesin molecule needs to deliver a force of $1.0\times 10^{-18}~N$
Work Step by Step
The impulse on the organelle is equal to its change in momentum. We can find the required force:
$F~t = m~(v_f-v_0)$
$F = \frac{m~(v_f-v_0)}{t}$
$F = \frac{(1.0\times 10^{-17}~kg)~(1.0\times 10^{-6}~m/s-0)}{10\times 10^{-6}~s}$
$F = 1.0\times 10^{-18}~N$
A kinesin molecule needs to deliver a force of $1.0\times 10^{-18}~N$.
