## College Physics (4th Edition)

A kinesin molecule needs to deliver a force of $1.0\times 10^{-18}~N$
The impulse on the organelle is equal to its change in momentum. We can find the required force: $F~t = m~(v_f-v_0)$ $F = \frac{m~(v_f-v_0)}{t}$ $F = \frac{(1.0\times 10^{-17}~kg)~(1.0\times 10^{-6}~m/s-0)}{10\times 10^{-6}~s}$ $F = 1.0\times 10^{-18}~N$ A kinesin molecule needs to deliver a force of $1.0\times 10^{-18}~N$.