## College Physics (4th Edition)

After the man catches the ball, the man is moving with a speed of $6.65~cm/s$
By conservation of momentum, the final momentum of the man and ball is equal to the initial momentum of the ball. We can find the final speed $v_f$ of the man and ball: $m_f~v_f = m_0~v_0$ $v_f = \frac{m_0~v_0}{m_f}$ $v_f = \frac{(0.20~kg)(25~m/s)}{75~kg+0.20~kg}$ $v_f = 0.0665~m/s = 6.65~cm/s$ After the man catches the ball, the man is moving with a speed of $6.65~cm/s$.