## College Physics (4th Edition)

The work required to hammer the nail a horizontal distance of 5.0 cm into the wall is $5.16~J$
We can find the total work required: $Work = F_1~d_1+F_2~d_2$ $Work = (50~N)(0.012~m)+(120~N)(0.038~m)$ $Work = 5.16~J$ The work required to hammer the nail a horizontal distance of 5.0 cm into the wall is $5.16~J$