College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 226: 2


The rope does $3120~J$ of work on the sled.

Work Step by Step

We can find the distance the sled moves in $10.0~s$: $d = v~t = (1.5~m/s)(10.0~s) = 15.0~m$ We can find the work done by the rope: $Work = F~d~cos~\theta$ $Work = (240~N)(15.0~m)~cos~30.0^{\circ}$ $Work = 3120~J$ The rope does $3120~J$ of work on the sled.
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