## College Physics (4th Edition)

The rope does $3120~J$ of work on the sled.
We can find the distance the sled moves in $10.0~s$: $d = v~t = (1.5~m/s)(10.0~s) = 15.0~m$ We can find the work done by the rope: $Work = F~d~cos~\theta$ $Work = (240~N)(15.0~m)~cos~30.0^{\circ}$ $Work = 3120~J$ The rope does $3120~J$ of work on the sled.