College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Multiple-Choice Questions - Page 226: 10

Answer

The correct answer is: (a) $\sqrt{3}~v$

Work Step by Step

We can find an expression for the speed when the catapult is stretched a distance $d$: $\frac{1}{2}mv^2 = \frac{1}{2}kd^2$ $v = d~\sqrt{\frac{k}{m}}$ We can find an expression for the speed when the catapult is stretched a distance $d$ and the mass of the pebble is $\frac{m}{3}$: $\frac{1}{2}(\frac{m}{3})v_2^2 = \frac{1}{2}kd^2$ $v_2 = d~\sqrt{\frac{3k}{m}}$ $v_2 = \sqrt{3}\times d~\sqrt{\frac{k}{m}}$ $v_2 = \sqrt{3}~v$ The correct answer is: (a) $\sqrt{3}~v$
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