## College Physics (4th Edition)

(a) $T = \frac{mv^2}{L}$ (b) $T = \frac{mv^2}{L~cos^2~\theta}$
(a) The rope's tension provides the centripetal force to keep the rock moving around in a circle. We can find the tension in the rope: $T = \frac{mv^2}{L}$ (b) The horizontal component of the rope's tension provides the centripetal force to keep the rock moving around in a circle. We can find the tension in the rope: $T~cos~\theta = \frac{mv^2}{L~cos~\theta}$ $T = \frac{mv^2}{L~cos^2~\theta}$