# Chapter 4 - Problems - Page 152: 72

(a) The coconut will strike the ground after $1.43~s$ (b) The coconut will strike the ground a horizontal distance of 25.7 meters from the release point.

#### Work Step by Step

(a) We can find the time it takes to reach the ground: $y = \frac{1}{2}at^2$ $t = \sqrt{\frac{2y}{a}}$ $t = \sqrt{\frac{(2)(10~m)}{9.80~m/s^2}}$ $t = 1.43~s$ The coconut will strike the ground after $1.43~s$ (b) We can find the horizontal displacement in this time: $x = v_x~t = (18~m/s)(1.43~s) = 25.7~m$ The coconut will strike the ground a horizontal distance of 25.7 meters from the release point.

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