## College Physics (4th Edition)

The person's acceleration is $0.82~m/s^2$ downward.
We can find the person's mass: $mg = 600~N$ $m = \frac{600~N}{9.80~m/s^2}$ $m = 61.2~kg$ Since the person's weight in the elevator is less than the person's weight on the ground, the person must be accelerating downward. Let $F_N$ be the upward force exerted on the person by the elevator. Note that $F_N = 550~N$. We can find the person's acceleration: $\sum F = ma$ $mg-F_N = ma$ $a = \frac{mg-F_N}{m}$ $a = \frac{600~N-550~N}{61.2~kg}$ $a = 0.82~m/s^2$ The person's acceleration is $0.82~m/s^2$ downward.