Answer
(a) It takes $1.565~s$ for a golf ball to fall from rest for a distance of 12.0 m
(b) In twice that time, the golf ball would fall $48.0~m$
Work Step by Step
(a) We can find the time it takes for a golf ball to fall from rest for a distance of 12.0 m:
$\Delta y = \frac{1}{2}at^2$
$t = \sqrt{\frac{2\Delta y}{a}}$
$t = \sqrt{\frac{(2)(12.0~m)}{9.80~m/s^2}}$
$t = 1.565~s$
It takes $1.565~s$ for a golf ball to fall from rest for a distance of 12.0 m
(b) We can find the distance the ball falls in twice that time, that is, in a time of $3.13~s$:
$\Delta y = \frac{1}{2}at^2$
$\Delta y = \frac{1}{2}(9.80~m/s^2)(3.13~s)^2$
$\Delta y = 48.0~m$
In twice that time, the golf ball would fall $48.0~m$
