## College Physics (4th Edition)

The two balls cross at more than half the height. Let $t=0$ be the moment when the second ball is thrown. If the time to reach height $h$ is $t$, the two balls will cross at time $\frac{t}{2}$, when the speeds of the two balls are equal. Between $t=0$ and $\frac{t}{2}$, the second ball's average speed is greater than the first ball's average speed as it drops from maximum height. Therefore, the second ball covers a greater distance than the first ball. The two balls cross at more than half the height.