## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 3 - Problems - Page 118: 101

#### Answer

We can rank the intervals in order of the velocity component $v_x$ from greatest positive to greatest negative: $EF \gt AB = CD \gt BC \gt DE$

#### Work Step by Step

The slope of the position versus time graph is the velocity. We can find the slope for each interval: AB: $v_x = \frac{\Delta x}{\Delta t} = \frac{20~m}{2~s} = 10~m/s$ BC: $v_x = \frac{\Delta x}{\Delta t} = \frac{0}{1~s} = 0~m/s$ CD: $v_x = \frac{\Delta x}{\Delta t} = \frac{10~m}{1~s} = 10~m/s$ DE: $v_x = \frac{\Delta x}{\Delta t} = \frac{-30~m}{1~s} = -30~m/s$ EF: $v_x = \frac{\Delta x}{\Delta t} = \frac{20~m}{1~s} = 20~m/s$ We can rank the intervals in order of the velocity component $v_x$ from greatest positive to greatest negative: $EF \gt AB = CD \gt BC \gt DE$

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