## College Physics (4th Edition)

The correct answer is: (d) 1020 m The area under the velocity versus time graph is the displacement. Each block in the graph is $1~m/s \times 120~s = 120~m$ From t = 0 to 10.0 minutes, there are 8.5 blocks under the graph. The displacement is $(8.5)(120~m) = 1020~m$ Since the jogger only travels north without changing direction, the distance is also 1020 meters.