## College Physics (4th Edition)

The correct answer is: (b) $2\frac{H}{\Delta t}$
The correct answer is: (b) $2\frac{H}{\Delta t}$ The average speed is $\frac{total~distance}{total~time}$ In this case, the total distance is $2H$ and the total time is $\Delta t$ Therefore, the average speed is $\frac{2H}{\Delta t}$