## College Physics (4th Edition)

We can write the reaction: $^{22}_{11}Na + ^{0}_{-1}e \rightarrow ^{22}_{10}Ne$ The daughter nuclide is $~~^{22}_{10}Ne$
During electron capture, an atom captures an electron and a proton is converted to a neutron. Therefore, in the daughter nuclide, the total number of nucleons stays the same, and the number of protons decreases by 1. The daughter nuclide has 22 nucleons and 10 protons. The element with 10 protons in the nucleus is neon. We can write the reaction: $^{22}_{11}Na + ^{0}_{-1}e \rightarrow ^{22}_{10}Ne$ The daughter nuclide is $~~^{22}_{10}Ne$