College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 29 - Problems - Page 1116: 9


$r = 5.7\times 10^{-15}~m$ $V = 7.80\times 10^{-43}~m^3$

Work Step by Step

The nucleus of an $^{107}_{43}Tc$ atom has 107 nucleons. We can find the radius of the nucleus: $r = (1.2\times 10^{-15}~m)~A^{1/3}$ $r = (1.2\times 10^{-15}~m)~(107)^{1/3}$ $r = 5.7\times 10^{-15}~m$ We can find the volume of the nucleus: $V = \frac{4}{3}~\pi~r^3$ $V = \frac{4}{3}~\pi~(5.7\times 10^{-15}~m)^3$ $V = 7.80\times 10^{-43}~m^3$
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