## College Physics (4th Edition)

$r = 5.7\times 10^{-15}~m$ $V = 7.80\times 10^{-43}~m^3$
The nucleus of an $^{107}_{43}Tc$ atom has 107 nucleons. We can find the radius of the nucleus: $r = (1.2\times 10^{-15}~m)~A^{1/3}$ $r = (1.2\times 10^{-15}~m)~(107)^{1/3}$ $r = 5.7\times 10^{-15}~m$ We can find the volume of the nucleus: $V = \frac{4}{3}~\pi~r^3$ $V = \frac{4}{3}~\pi~(5.7\times 10^{-15}~m)^3$ $V = 7.80\times 10^{-43}~m^3$