Answer
The correct answer is:
(a) The electron has more kinetic energy and a higher speed.
Work Step by Step
We can write an expression for the de Broglie wavelength of the electron:
$\lambda_e = \frac{h}{m_e~v_e}$
We can write an expression for the de Broglie wavelength of the neutron:
$\lambda_n = \frac{h}{m_n~v_n}$
Since they both have the same de Broglie wavelength, then:
$m_e~v_e = m_n~v_n$
Since $m_e \lt m_n$, then $v_e \gt v_n$
Then, the kinetic energy of the electron must be greater than the kinetic energy of the neutron (since $K = \frac{1}{2}mv^2$)
The correct answer is:
(a) The electron has more kinetic energy and a higher speed.
