College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 27 - Problems - Page 1045: 73


$\lambda = 6.2\times 10^{-12}~m$

Work Step by Step

We can find the wavelength of a photon produced by a 0.20-MV x-ray machine: $E = \frac{hc}{\lambda}$ $q~\Delta V = \frac{hc}{\lambda}$ $\lambda = \frac{hc}{q~\Delta V}$ $\lambda = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{(1.6\times 10^{-19}~C)(0.20\times 10^6~V)}$ $\lambda = 6.2\times 10^{-12}~m$
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