## College Physics (4th Edition)

$\lambda = 6.2\times 10^{-12}~m$
We can find the wavelength of a photon produced by a 0.20-MV x-ray machine: $E = \frac{hc}{\lambda}$ $q~\Delta V = \frac{hc}{\lambda}$ $\lambda = \frac{hc}{q~\Delta V}$ $\lambda = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{(1.6\times 10^{-19}~C)(0.20\times 10^6~V)}$ $\lambda = 6.2\times 10^{-12}~m$