## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 27 - Problems - Page 1044: 70

#### Answer

The minimum amount of energy required to change from one isomer to another is $2.0~eV$

#### Work Step by Step

We can find the energy of a photon with a wavelength of $630~nm$: $E = \frac{hc}{\lambda}$ $E = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{630\times 10^{-9}~m}$ $E = (3.16\times 10^{-19}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$ $E = 2.0~eV$ The minimum amount of energy required to change from one isomer to another is $2.0~eV$

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