College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 27 - Multiple-Choice Questions - Page 1041: 10


The correct answer is: (f) $~~~(a)~and~(b)$

Work Step by Step

We can write an expression for $K_{max}$, the maximum kinetic energy of an electron in the experiment: $K_{max} = \frac{hc}{\lambda}-\phi$ The stopping potential is proportional to the value of $K_{max}$. Therefore, the stopping potential is determined by $\lambda$, the wavelength of the incident light, and $\phi$, the work function of the metal. The correct answer is: (f) $~~~(a)~and~(b)$
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