## College Physics (4th Edition)

The correct answer is: (f) $~~~(a)~and~(b)$
We can write an expression for $K_{max}$, the maximum kinetic energy of an electron in the experiment: $K_{max} = \frac{hc}{\lambda}-\phi$ The stopping potential is proportional to the value of $K_{max}$. Therefore, the stopping potential is determined by $\lambda$, the wavelength of the incident light, and $\phi$, the work function of the metal. The correct answer is: (f) $~~~(a)~and~(b)$