## College Physics (4th Edition)

$E = 9.0\times 10^{13}~N$
We can find the amount of energy that is released: $E = mc^2$ $E = (1.0\times 10^{-3}~kg)(3.0\times 10^8~m/s)^2$ $E = 9.0\times 10^{13}~N$