## College Physics (4th Edition)

We can find the frequency when the wavelength is $190~m$: $f = \frac{c}{\lambda} = \frac{3.0\times 10^8~m/s}{190~m} = 1.58\times 10^6~Hz = 1580~kHz$ We can find the frequency when the wavelength is $550~m$: $f = \frac{c}{\lambda} = \frac{3.0\times 10^8~m/s}{550~m} = 5.45\times 10^5~Hz = 545~kHz$ We can find the range: $1580~kHz - 545~kHz = 1035~kHz$ We can find the number of frequency bands 10 kHz wide that can fit inside this range: $\frac{1035~kHz}{10~kHz} = 103.5$ 103 stations can operate in the broadcast band.