## College Physics (4th Edition)

The ratio of the transmitted intensity to the incident intensity is $\frac{1}{16}$
We can write an expression for the incident intensity: $I_1 = c~\epsilon_0~E_1^2$ We can write an expression for the transmitted intensity: $I_2 = c~\epsilon_0~E_2^2$ $I_2 = c~\epsilon_0~(\frac{E_1}{4})^2$ $I_2 = \frac{1}{16}\times c~\epsilon_0~E_1^2$ $I_2 = \frac{1}{16}\times I_1$ The ratio of the transmitted intensity to the incident intensity is $\frac{1}{16}$