## College Physics (4th Edition)

The magnitude of this force is $157~N$ and it is directed at an angle of $57.2^{\circ}$ below the +x-axis.
We can find the magnitude of this force: $F = \sqrt{F_x^2+F_y^2} = \sqrt{(85~N)^2+(-132~N)^2} = 157~N$ We can find the angle $\theta$ below the positive x-axis: $tan~\theta = \frac{132~N}{85~N}$ $\theta = tan^{-1}(\frac{132~N}{85~N})$ $\theta = 57.2^{\circ}$ The magnitude of this force is $157~N$ and it is directed at an angle of $57.2^{\circ}$ below the +x-axis.