College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems - Page 70: 91

Answer

The tension in the upper cord is $12.4~N$ The tension in the lower cord is $8.3~N$

Work Step by Step

The tension $T_u$ in the upper cord is equal in magnitude to the component of the total weight of both boxes that is directed down the ramp. We can find this tension: $T_u = (1.0~kg+2.0~kg)~g~sin~\theta$ $T_u = (1.0~kg+2.0~kg)~(9.80~m/s^2)~sin~25^{\circ}$ $T_u = 12.4~N$ The tension $T_l$ in the lower cord is equal in magnitude to the component of the weight of the 2.0 kg box that is directed down the ramp. We can find this tension: $T_l = (2.0~kg)~g~sin~\theta$ $T_l = (2.0~kg)~(9.80~m/s^2)~sin~25^{\circ}$ $T_l = 8.3~N$
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