Answer
The normal force is $152.8~N$
The magnitude of the force of static friction exerted on the crate is $88.2~N$ and this force is directed up the ramp at an angle of $30^{\circ}$ to the horizontal.
Work Step by Step
The normal force $F_N$ is the component of the crate's weight that is directed straight into the surface of the ramp.
$F_N = mg~cos~\theta$
$F_N = (18.0~kg)(9.80~m/s^2)~cos~30^{\circ}$
$F_N = 152.8~N$
The normal force is $152.8~N$
Since the crate is not moving, the force of static friction is exerted on the crate and it is directed up the ramp. The force of static friction $F_f$ exerted on the crate is equal in magnitude to the component of the crate's weight directed down the ramp.
$F_f = mg~sin~\theta$
$F_f = (18.0~kg)(9.80~m/s^2)~sin~30^{\circ}$
$F_f = 88.2~N$
The magnitude of the force of static friction exerted on the crate is $88.2~N$ and this force is directed up the ramp at an angle of $30^{\circ}$ to the horizontal.
