College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Problems - Page 759: 94

Answer

The minimum radius is 21 cm

Work Step by Step

We can use Newton's second law to find an expression for the force required to make an object move in a circle: $F = ma$ $F = m~\frac{v^2}{r}$ We can write an expression for the magnetic force: $F = qvB$ We can equate the two expressions for $F$ to find the minimum required value for $r$: $\frac{mv^2}{r} = qvB$ $r = \frac{mv}{qB}$ $r = \frac{(1.67\times 10^{-27}~kg)(3.0\times 10^7~m/s)}{(1.6\times 10^{-19}~C)(1.5~T)}$ $r = 0.21~m$ The minimum radius is 21 cm We can see that this result comes from Newton's second law $F = ma$
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