College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Problems - Page 755: 47

Answer

(a) The minimum possible magnitude of the magnetic field is $0.50~N$ (b) The information enables us to calculate the minimum possible magnitude of the magnetic field in the case when the angle $\theta$ is $90^{\circ}$. However, the magnitude of the magnetic field could be greater than this magnitude depending on the angle $\theta$.

Work Step by Step

(a) We can find the minimum possible magnitude of the magnetic field: $F = I~L~B~sin~\theta$ $B = \frac{F}{I~L~sin~\theta}$ $B = \frac{4.12~N}{(33.0~A)(0.25~m)~sin~\theta}$ $B = \frac{0.50}{sin~\theta}~T$ The minimum possible magnitude of the magnetic field is $0.50~N$ (b) The information enables us to calculate the minimum possible magnitude of the magnetic field in the case when the angle $\theta$ is $90^{\circ}$. However, the magnitude of the magnetic field could be greater than this magnitude depending on the angle $\theta$.
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