College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Problems - Page 754: 37


$v = 4.22\times 10^6~m/s$

Work Step by Step

If the net force is zero, the magnitude of the force from the magnetic field must be equal in magnitude to the force from the electric field. We can find the speed of the electron: $q~v~B = E~q$ $v = \frac{E}{B}$ $v = \frac{2.68\times 10^6~V/m}{0.635~T}$ $v = 4.22\times 10^6~m/s$
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