College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 699: 30


(a) $R = 15~\Omega$ (b) $R = 10~\Omega$

Work Step by Step

(a) We can find the resistance at point 1: $V = I~R$ $R = \frac{V}{I}$ $R = \frac{0.3~V}{0.02~A}$ $R = 15~\Omega$ (b) We can find the resistance at point 2: $V = I~R$ $R = \frac{V}{I}$ $R = \frac{0.4~V}{0.04~A}$ $R = 10~\Omega$
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