## College Physics (4th Edition)

$W = 3.2\times 10^{-17}~J$
We can find the work done by the electric field: $W = -\Delta U$ $W = -q~\Delta V$ $W = -q~(V_2-V_1)$ $W = -(-1.6\times 10^{-19}~C)~[100~V-(-100~V)]$ $W = 3.2\times 10^{-17}~J$