Answer
$Q = 1.8\times 10^{-5}~C$
Work Step by Step
We can find the magnitude of the charge on each plate:
$Q = C~\Delta V$
$Q = (2.0\times 10^{-6}~F)(9.0~V)$
$Q = 1.8\times 10^{-5}~C$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 17 - Problems - Page 655: 55
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