College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 655: 55


$Q = 1.8\times 10^{-5}~C$

Work Step by Step

We can find the magnitude of the charge on each plate: $Q = C~\Delta V$ $Q = (2.0\times 10^{-6}~F)(9.0~V)$ $Q = 1.8\times 10^{-5}~C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.