## College Physics (4th Edition)

The correct answer is: (e) $\frac{N \cdot m}{C}$
We can write an equation for electric potential around a point charge $q$: $V = \frac{k~q}{r}$ $k$ is measured in units of $N~m^2/C^2$ $q$ is measured in units of $C$ $r$ is measured in units of $m$ We can find the units for electric potential: $\frac{(N~m^2/C^2)(C)}{m} = \frac{N~m}{C}$ The correct answer is: (e) $\frac{N \cdot m}{C}$