College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Conceptual Questions - Page 650: 21


see solution

Work Step by Step

The charge remains the same as the plates are isolated. As the plates move closer, d decreases and thus capacitance increases. $Q =CV$, $Q $is constant, so $ V$ must decrease. And the electric field remains constant. Energy stored decreases as well.
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